# H0836 — compliant buffering: complete conditional proofs and counterexamples **Status:** the circuit-model results below are proved. Reduced physical sand breakthrough is not established. No new buffering principle is claimed. ## Model and assumptions Consider a fluid-storage node with constant positive compliance C and a linear downstream hydraulic resistance R>0. Pressure p is measured relative to the downstream outlet; inflow is u(t), outflow is y(t)=p(t)/R. Conservation gives C dp/dt = u−p/R, τ dy/dt + y = u, τ=RC>0. The baseline is subtracted and initially equilibrated. Assume no inertia, resonance, cavitation, leakage, hysteresis, or deformation-dependent resistance. Comparing the rigid limit uses the same R and specified inlet waveform, with C=0 giving y=u. These assumptions are not yet a model of particle transport. ## Theorem 1: exact attenuation Multiplying the differential equation by exp(t/τ) and integrating gives the zero-state solution y(t)=∫₀∞ k(s)u(t−s)ds, k(s)=exp(−s/τ)/τ for s≥0. For a nonzero-frequency sinusoid of amplitude A, inserting a complex exponential gives transfer function H(iω)=1/(1+iωτ), output amplitude = A/√(1+(ωτ)²) < A. The DC gain is 1; this model does not remove the mean flow. For a positive rectangular pulse with A>0, u=A on [0,T] and zero otherwise, y=A(1−exp(−t/τ)) for 0≤t≤T, y=A(1−exp(−T/τ))exp(−(t−T)/τ) for t≥T. The first branch increases and the second decreases, so peak(y)=A(1−exp(−T/τ))0.1, otherwise 0. Take A=T=τ=1. Rigid flow exceeds the threshold for exactly one time unit. Buffered flow crosses it during the rise at t↑=−ln(0.9), and during decay at t↓=1+ln((1−exp(−1))/0.1). Its modeled release duration is t↓−t↑≈2.73855>1, although its peak is only 1−exp(−1)≈0.6321. This explicitly refutes the inference that a lower peak alone guarantees less integrated particle release. The counterexample closure is deliberately nonconvex and is not asserted to describe real sand. ## Counterexample 2: equal inlet waveform is not equal hydraulic work For this energy comparison use zero initial and final flow and pressure, not an unspecified nonzero operating baseline. Pump work is W=∫p u dt. Multiplying conservation by p and integrating over a complete return to equilibrium gives W = R∫y²dt + (C/2)[p²]initial to final = R∫y²dt. For the rectangular pulse, Wbuffer=R A²[T−τ(1−exp(−T/τ))], Wrigid=R A²T. Consequently the same inlet pulse does not supply the same work. With R=T=τ=1, compare a rigid amplitude 1 with a buffered amplitude exp(1/2). Both have work 1, but the buffered peak is exp(1/2)−exp(−1/2)=2sinh(1/2)>1. The strict inequality follows from sinh(x)>x for x>0. This equal-work example does not also match total injected volume; it demonstrates a limitation of energy matching alone, not a refutation of every jointly controlled physical experiment. ## Exact conclusion Linear compliant storage attenuates matched-waveform fluctuations. A specific convex release closure then bounds integrated modeled release. Neither attenuation nor that closure establishes the original sand-breakthrough claim under all the original matching conditions. Experiments must establish actual compliance, resistance, flow and pressure histories, energy, volume, and release kinetics.