# H0346 — perforated hydrogel skin: a complete transport-model proof **Status:** the stated lumped transport result is proved. Its applicability to a real swelling gel remains an experimental question. The calculation is not a new transport law. ## Original claim and the ambiguity to remove The original claim says sparse perforations reduce swelling delay by more than their fractional open area. Define that precisely as D(φ) = 1 − t_half(φ)/t_half(0) > φ, where φ is the perforated fraction of skin area, 0<φ<1, and t_half is time to half of equilibrium uptake. This comparison is a defined dimensionless criterion, not a general meaning of “more than expected.” It is not a claim to exceed a correctly specified area-weighted permeability model. ## Model assumptions Normalize total surface area to one. Let k_s>0 be conductance of intact skin per unit area, k_h≥k_s conductance through a hole, and b>0 bulk conductance behind the skin. Skin and hole pathways act in parallel; the resulting surface layer and bulk act in series. Their conductances are linear, constant, and independent of swelling. Let S>0 be a fixed storage coefficient. The interior is represented by one well-mixed potential, and the bath potential is a fixed step. Perforating the skin leaves equilibrium capacity S unchanged. There are no access/spreading resistances, inter-hole interactions, cracks, changing modulus, nonlinear osmotic effects, or additional exposed edges. These are explicit model restrictions. Real poroelastic gels need not behave as a single well-mixed storage element. ## Theorem 1: exact half-time and monotonicity Parallel conductance is g(φ)=(1−φ)k_s+φk_h=k_s+φd, d=k_h−k_s≥0. Series addition gives G(φ)=1/(1/b+1/g(φ)). If z is normalized uptake, conservation is S dz/dt=G(φ)(1−z), z(0)=0. Separating variables gives z(t)=1−exp(−G(φ)t/S), t_half(φ)=S ln(2)[1/b+1/g(φ)]. Differentiation yields dt_half/dφ=−S ln(2)d/[k_s+φd]²≤0. For d>0, half-time strictly decreases with perforated area. For d=0 it is unchanged. ∎ ## Theorem 2: exact condition for delay reduction exceeding open fraction Direct algebra gives D(φ)= b φd / [(k_s+φd)(b+k_s)]. For φ>0, all denominators are positive, so D(φ)>φ iff b d > (k_s+φd)(b+k_s) iff d[b−φ(b+k_s)] > k_s(b+k_s). This last inequality is a necessary and sufficient condition. Equivalently, the effect requires φ < b/(b+k_s) and d > k_s(b+k_s)/[b−φ(b+k_s)]. If b−φ(b+k_s)≤0, the claimed inequality is impossible. This establishes both the predicted regime and its failure regime without a numerical fit. ∎ ## An exact example Use consistent arbitrary conductance units and set b=1, k_s=1/100, k_h=1, φ=1/100. Then g=199/10000, and D=9900/20099≈0.492562, t_half(φ)/t_half(0)=10199/20099≈0.507438. Thus a 1% opening fraction produces about a 49.26% half-time reduction within this model. This is a constructed mathematical example, not a measured gel result or a predicted performance specification. ## Counterexamples and limits 1. If k_h=k_s, perforations provide no transport contrast and D=0. 2. For fixed k_s,k_h,φ, letting b→0 gives D→0. If bulk transport is the bottleneck, opening the skin has arbitrarily little effect. 3. If k_h