An original arithmetic puzzle. This is not Reed–Solomon coding or a QR decoder. Assume the check totals are intact, the three slots stay in order and exactly one data value changed.
| Item | Value |
|---|---|
| Original ordinary total | 13 |
| Original weighted total: slot 1 + 2×slot 2 + 3×slot 3 | 24 |
| Received values, in order | 4, 9, 2 |
The received total is 15, a change of +2. The weighted total is 28, a change of +4. The ratio 4÷2=2 identifies slot 2 under the stated assumptions. Subtract 2 from 9 to restore 7. The values 4, 7, 2 satisfy both totals.
Now receive 6, 7, 4. Both outer values changed. The ordinary total is 17 and the weighted total is 32. Their changes are +4 and +8, which misleadingly suggest slot 2. Subtracting 4 there yields 6, 3, 4: both checks pass, but the original 4, 7, 2 has not been recovered.
A correction method has a designed error model. Passing these two checks is not proof against arbitrary multiple changes or damaged checks.
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